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Find the approximate value of (2.01), wh...

Find the approximate value of (2.01), where f (x) = `4x^(2)` + 5x + 2.

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The correct Answer is:
28.21
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NCERT TAMIL-APPLICATION OF DERIVATIVES-EXERCISE 6.4
  1. Using differentials, find the approximate value of each of the up to 3...

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  2. Using differentials, find the approximate value of each of the up to 3...

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  3. Using differentials, find the approximate value of each of the up to 3...

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  4. Using differentials, find the approximate value of each of the up to 3...

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  5. Using differentials, find the approximate value of each of the up to 3...

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  6. Using differentials, find the approximate value of each of the up to 3...

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  7. Using differentials, find the approximate value of each of the up to 3...

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  8. Using differentials, find the approximate value of each of the up to 3...

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  9. Using differentials, find the approximate value of each of the up to 3...

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  10. Using differentials, find the approximate value of each of the up to 3...

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  11. Using differentials, find the approximate value of each of the up to 3...

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  12. Using differentials, find the approximate value of each of the up to 3...

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  13. Find the approximate value of (2.01), where f (x) = 4x^(2) + 5x + 2.

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  14. Find the approximate value of (5.001), where f(x) = x^(3) – 7x 2 + 15...

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  15. Find the approximate change in the volume V of a cube of side x metres...

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  16. Find the approximate change in the surface area of a cube of side x me...

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  17. If the radius of a sphere , is measured as 7m with an error of 0.02 m ...

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  18. If the radius of a sphere is measured as 9 m with an error of 0.03 m, ...

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  19. If f(x) = 3x^(2) + 15x + 5, then the approximate value of f (3.02) is

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  20. The approximate change in the volume of a cube of side x metres caused...

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