Let ABCD be a traezium with AD parallel to BC. Assume there is a point M in the interior of the segement BC such that AB=AM and DC=DM . Then the ratio of the area of the tapezium to the area of triabgle AMD is -

In the adjoining figure,DE is parallel to BC and AD=11m,BD=2cm. What is the ratio of the area of ABC to the area of ADE?

ABCD is a trapezium in which AB||DC and let E be the mid point of AD. Let F be a point on BC such that EF||AB. Prove that EF=1/2(AB+DC)

ABCD is a trapezium with AB////DC . A line parallel to AC intersects Ab at point M and BC at point N. Prove that : "area of" DeltaADM= "area of" DeltaACN .

ABCD is a trapezium with AB //DC. A line parallel to AC intersects AB at point M and BC at point N. Prove that: area of triangleADM=area of triangleACN.

ABCD is a quadrillateral, with AD parallel to BC (see figure). E is a point between A and D such that BE represents the height of ABCD and E is the midpoint of AD. If the area of triangle ABE is 12.5 square inches, what is the area of ABCD?

ABCD is a trapezium in which AB||DC and let E be the mid point of AD. Let F be a point on BC such that EF||AB. Prove that F is mid point of BC.

In trapezium ABCD, sides AB and DC are parallel to each other. E is mid-point of AD and F is mid-point of BC. Prove that : AB + DC = 2EF.

ABCD is a trapezium with AB parallel to DC. A line parallel to AC intersects AB at X and BC at Y. Prove that area of DeltaADX = area of DeltaACY .

ABCD is a trapezium with AB parallel to DC. A line parallel to AC intersects AB at X and BC at Y. Prove that area of DeltaADX = area of DeltaACY .