If velocity is given by following function V = `x^2` . Then find out relation between x & t (assume x = 1 m at t = 0)

The acceleration of a particle which is depend on time is given by following function a = 2t + 1 and at time t = 0, x = 1m and ui = 2m/s. Then find out displacement of the particle at t = 3 sec.

The velocity of an object is changing with time and relation is given by the following equation. v=2t+3t^(2) Calculate the position of the object from the origin at t = 2 s. Assume particle to be at origin at t = 0

The velocity of an object is changing with time and relation is given by the following equation. v=2t+3t^(2) Calculate the position of the object from the origin at t = 2 s. Assume particle to be at origin at t = 0

A particle moves along x- axis. It's velocity is a function of time according to relation V=(3t^(2)-18t+24)m//s assume at t=0 particle is at origin. Which of the following graph may be correct for the motion of particle

A particle moves along x- axis. It's velocity is a function of time according to relation V=(3t^(2)-18t+24)m//s assume at t=0 particle is at origin. Which of the following graph may be correct for the motion of particle

A particle moves along x- axis. It's velocity is a function of time according to relation V=(3t^(2)-18t+24)m//s assume at t=0 particle is at origin. Distance travelled by particle in 0 to 3 second time interval is :

A particle moves along x- axis. It's velocity is a function of time according to relation V=(3t^(2)-18t+24)m//s assume at t=0 particle is at origin. Distance travelled by particle in 0 to 3 second time interval is :

A particle moves along x- axis. It's velocity is a function of time according to relation V=(3t^(2)-18t+24)m//s assume at t=0 particle is at origin. Time interval in which particle speed continuous decreases?

A particle moves along x- axis. It's velocity is a function of time according to relation V=(3t^(2)-18t+24)m//s assume at t=0 particle is at origin. Time interval in which particle speed continuous decreases?