f(dx)/(1+tan x)

If f(x)=(1+ tan x) [1+ tan(pi/4 - x)] and g(x) is a function with domain R, then int_(0)^(1) x^(3) g o f (x) dx=

(d)/(dx)((1-tan x)/(1+tan x))*(d)/(dx)((1-tan x)/(1+tan x))

int ("tan"x)/(1 + tan x )dx

The range of f(x)=(1-tan x)/(1+tan x) is

The range of f(x)=(1-tan x)/(1+tan x) is

If y = sqrt((1 + tan x)/(1 - tan x)) " then " (dy)/(dx)= ?

If Y = (1 + tan x)/(1 - tan x) , then (dy)/(dx) is

If Y = (1 + tan x)/(1 - tan x) , then (dy)/(dx) is

" (.) "int(tan x)/(1+tan x)dx

y=[(1-tan x)/(1+tan x)], then the value of (dy)/(dx)