What volume of 6M HCl and 2M HCl should be mixed to get one litre of 3M HCl?

Explanation

Suppose the volume of 6M HCl required to obtain 1L of 3M HCl = XL
Volume of 2M HCl required = (1-x)L
Applying the molarity equation
`M_1 V_1 + M_2V_2 = M_3V_3 `
`6 MHCl + 2MHCl = 3MHCl`
`6x+2(1-x) = 3 xx 1`
`6x + 2 -2x = 3 `
` 4x =1 `
`x =0.25 L`
hence, volume of 6 M HCl rquired = 0.25 L
Volume of 2M HCl required = 0.75 L