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75 ml of gas A effuses through a pin hol...

75 ml of gas A effuses through a pin hole in 73 seconds the same volume of `SO_(2)` under indential conditions effuses in seconds. Calculate the molecular mass of A.

Text Solution

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`("Effusion rate of" CO_(2)) /("Effusion rate of A") = sqrt((M_(A))/(M_(CO_(2))))`
`(50/115)/(50/146) = sqrt((M_(A))/(44)) , (1.27)^(2) = (M_(A))/(44)`
`M_(A) = 71 therefore` Molecular mass of A is 71 .
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