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The decomposition of phosphine (PH(3)) o...

The decomposition of phosphine `(PH_(3))` on tungsten at low pressure is a first order reaction. It is because the

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`(t_(1))/(t_(2))=((a_(2))/(a_(1)))^(n-1)`
`a_(1)="290 mm of Hg "t_(1)="263 seconds"`
`a_(2)="360 mm of Hg "t_(2)="212 seconds"`
`(263)/(212)=((360)/(290))^(n-1)`
`1.24=(1.24)^(n-1)`
`n-1=1`
`n=1+1=2`
Hence, the reaction is of second order.
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