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The emf of the half cell Cu^(2+)""((aq))...

The emf of the half cell `Cu^(2+)""_((aq))//Cu_((s))` containing 0.01 M `Cu^(2+)` solution is +0.301 V. Calculate the standard emf of the half cell.

Text Solution

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`n-2, E_(Cu^(2+)//Cu)^(@)=0.359V`
Hint : `E_(Cu^(2+)//Cu)=E_(Cu^(2+)//Cu)^(@)-(0.0591)/(2)log""(1)/([Cu^(2+)])`
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