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If E(1)=0.5V corresponds to Cr^(3+)+3e^(...

If `E_(1)=0.5V` corresponds to `Cr^(3+)+3e^(-) rarr Cr_((s)) " and " E_(2)=0.41V` corresponds to `Cr^(3+)+e^(-) rarr Cr^(2+)` reactions, calculate the emf `(E_(3))` of the reaction `Cr^(2+)+2e^(-) rarr Cr_((s))`.

Text Solution

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0.655V
Hint : `E_(3)=(3E_(1)-E_(2))/(2)`
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