Home
Class 12
CHEMISTRY
Calculate the emf of the cell Zn//ZnO(2)...

Calculate the emf of the cell `Zn//ZnO_(2), OH^(-)""_(aq),-HgO""//Hg` given that `E^(@)` values of `OH^(-), ZnO` and `OH^(-), HgO""//Hg` half cells are -1.216 V and 0.098 V respectively.

Text Solution

Verified by Experts

Hint : `E^(@)=E_(R)^(@)-E_(L)^(@),E^(@)=1.314V`
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY - II

    NCERT TAMIL|Exercise SELF EVALUATION((C) Answer not exceeding sixty words :)|2 Videos
  • ELECTRO CHEMISTRY - I

    NCERT TAMIL|Exercise SELF EVALUATION((D) Solve the problems :)|10 Videos
  • ETHERS

    NCERT TAMIL|Exercise SELF EVALUATION ((D) Answer not exceeding sixty words :)|6 Videos

Similar Questions

Explore conceptually related problems

The emf of the cell Cd//CdCl_(2)," "25H_(2)O" "//AgCl_((s))Ag is 0.675 V. Calculate of the cell reaction.

Calculate the emf of the cell. Zn|Zn^(2+)(0.001M)||Ag^(+)(0.1M)|Ag The standard potential of Ag//Ag^(+) half - cell is +0.80 V and Zn//Zn^(2+) is -0.76V.

The equilibrium constant of cell reaction: Ag_((s))+Fe^(3+) iff Fe^(2+)+Ag^(+) is 0.335 at 25^(@)C . Calculate the standard emf of the cell Ag//Ag^(+), Fe^(3+), Fe^(2+)//Pt . Calculate E^(@) of the half cell Fe^(3+), Fe^(2+)//Pt is 0.7791 V Calculate E^(@) of Fe^(3+), Fe^(2+)//Pt half cell.

The emf of the half cell Cu^(2+)""_((aq))//Cu_((s)) containing 0.01 M Cu^(2+) solution is +0.301 V. Calculate the standard emf of the half cell.

The emf values of the cell reactions Fe^(3+)+e^(-) rarr Fe^(2+) " and " Ce^(2+) rarr Ce^(3+) e^(-) are 0.61 V and -0.85 V respectively. Construct the cell such that the free energy of the cell is negative. Calculate the emf of the cell.