I=int_(0)^( pi)x sin xdx

int_(0)^( pi/2)x sin xdx

Evaluate: int_(0)^( pi/2)x sin xdx

Evaluate: int_(0)^( pi/2)x sin xdx

int_(0)^( pi)sin xdx

If f:[0,pi]rarr R is continuous and int_(0)^( pi)f(x)sin xdx=int_(0)^( pi)f(x)cos xdx=0 then the number of roots of f(x) in (0,pi) is ...

If I_(1) = int_(0)^(pi) (x sin x)/(1+cos^2x) dx , I_(2) = int_(0)^(pi) x sin^(4)xdx then, I_(1) : I_(2) is equal to

If I_(1) = int_(0)^(pi) (x sin x)/(1+cos^2x) dx , I_(2) = int_(0)^(pi) x sin^(4)xdx then, I_(1) : I_(2) is equal to

int_(0)^( pi)x sin^(3)xdx

"int_(0)^( pi)x sin^(2)xdx