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Find the specific ehat capacity of ice i...

Find the specific ehat capacity of ice if 12 kg of ice absorbs 50.4 kJ of heat to raise its temperature from `-20^(@)C" to "0^(@)C`.

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The specific heat of ice at 0^@C is

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A calorimeter contains ice. Determine the heat capacitiy of the calorimeter if 2.1kJ of heat is required to heat it togheter with its contents from 270^(@)K to 270^(@)K , and 69.72kJ of heat of required to raise its temperature of 272K to 274^(@)K . ( L of ice =336xx10^(3)Jkg^(-1) , specific heat capacity of ice =2100kg^(-1)K^(-1) )

A 2.00 kg metal object requires 5.02 xx 10^(3) J of heat to raise its temperature from 20.0^(@)C to 40.0^(@)C . What is the specific heat capacity of the metal ?

A substance of mass 1cdot5 kg absorbs 45 kcal of heat energy. If its temperature rises from 28^(@)C" to "38^(@)C , find its specific heat capacity.

Latent heat of fusion of ice is 6.02 Kj "mol"^(-1) . The heat capacity of water is 4.18 J g^(-1) C^(-1) , 500 g of liquid water is to be cooled from 20^(@) C to 0^(@) C. Find the number of ice cubes (one mole each) required.

Find the final temeprature and composition of the mixture of 1 kg of ice at -10^(@)C and 4.4 kg of water at 30^(@)C . Given that specific heat of water is 4200J//kg^(@)C and that of ice is 2100J//kg^(@)C and latent heat of fusion of ice is 3.36xx10^(5) J/kg

A calorimeter of mass 60 g contains 180 g of water at 29^(@)C . Find the final temperature of the mixture, when 37.2 g of ice at - 10^(@)C is added to it (specific heat capacity of water = 4200 J//kg K. latent heat of ice 336 xx 10^(3)J//kg . Specific heat capacity of ice = 2100 J//kg K , specific heat capacity of the calorimeter is 0.42 Jg^(-1) xx C^(-1) )

Calcuate the heat required to convert 0.6 kg of ice at - 20^(@)C , kept in a calorimeter to steam at 100^(@)C at atmospheric pressure. Given the specific heat capacity of ice =2100 j kg^(-1) K^(-1) , specific heat capacity of water =4186 j kg^(-1) K^(-1) latent heat ice =3.35xx10^(5) j kg^(-1) and latent heat of steam =2.256xx10^(6)j kg^(-1)