If `tan(A+B)tan(A-B)` = ______________.

If tan (A+B)=p, tan(A-B)=q find tan 2A.

If tan(A+B)=p&tan(A-B)=q , then the value of tan 2A is

If tan(A+B)=m , tan (A-B)=n, " then " tan 2A=

If tan(A+B)=pand tan(A-B)=q, then the value of tan2A, is

If tan(A+B)=pand tan(A-B)=q, then the value of tan2A, is

Prove that, tan (B - C) + tan (C -A ) + tan (A -B) = tan (B-C) tan (C-A) tan (A -B)

If tan (x-A)tan (x-B)+tan (x-B)tan (x-C)+tan(x-C)tan (x-A)=1 and A,B and C are the angles of triangle ABC then find x

If tan (x-A)tan (x-B)+tan (x-B)tan (x-C)+tan(x-C)tan (x-A)=1 and A,B and C are the angles of triangle ABC then find x

"Prove that" tan (A+B) - tan (A - B) = (sin2 B)/(cos^(2)B - sin^(2) A).

(tan A + tan B) / (tan (A + B)) + (tan A-tan B) / (tan (AB)) =