`xcos^(2)ydx-ycos^(2)xdy=0`

x cos^(2)ydx=ycos^(2)xdy A) xsin2y=ycos2x+c B) x tanx=ytany+c C) x tan x-y tan y=ln(secx/ sec y)+c D) x sec x=y sec y+c

General solution of coty cos^(2)xdy+cotxcos^(2)ydx=0 is

(1+xy)ydx+(1-xy)xdy=0

sec^(2)xtan^(2)ydx+sec^(2)ytan^(2)xdy=0

xdy-ydx=xy^(2)dx

The solution of the differential equation (1+x^(2)y^(2))ydx+(x^(2)y^(2)-1)xdy=0 is

Solve : {xcos(y/x)+ysin(y/x)}ydx={ysin(y/x)-xcos(y/x)}xdy

Solve : {xcos(y/x)+ysin(y/x)}ydx={ysin(y/x)-xcos(y/x)}xdy

Solve : {xcos(y/x)+ysin(y/x)}ydx={ysin(y/x)-xcos(y/x)}xdy

dx-dy+ydx+xdy=0