The area of the parallelogram formed by the lines 3x + 4y = 7a; 3x + 4y = 7b; 4x + 3y-7c and 4x+3y = 7d is-

The area of the parallelogram formed by the lines 3x-4y + 1=0, 3x-4y +3=0,4x-3y-1=0 and 4x -3y -2 =0, is (A) 1/7 sq units (B) 2/7 sq units (C) 3/7 sq units (D) 4/7 sq units

Prove that the area of the parallelogram formed by the lines 3x-4y+a=0,\ 3x-4y+3a=0,\ 4x-3y-a=0\ a n d \4x-3y-2a =0\ i s (2a^2)/7s qdotu n i t sdot

Prove that the area of the parallelogram formed by the lines 3x-4y+a=0,\ 3x-4y+3a=0,\ 4x-3y-a=0 and 4x-3y-2a=0 is (2a^2)/7 sq. units

The area of the parallelogram formed by the lines 3x-4y+1=0,3x-4y+3=0,4x-3y-1=0 and 4x-3y-2=0, is (A) (1)/(7) squnits (B) (2)/(7) squnits (C) (3)/(7) squnits (D) (4)/(7) squnits

The area of the parallelogram formed by the lines 4y-3x-a=0, 3y-4x+a=0, 4y-3x-3a=0, 3y-4x+2a=0 is

Prove that the area of the parallelogram contained by the lines 4y-3x-a=0,3y-4x+a=0,4y-3x-3a=0 and 3y-4x+2a=0 is ((2)/(7))a^(2)

Prove that the area of the parallelogram contained by the lines 4y-3x-a=0,3y-4x+a=0,4y-3x-3a=0, and 3y-4x+2a=0 is (2/7)a^2dot

Prove that the area of the parallelogram contained by the lines 4y-3x-a=0,3y-4x+a=0,4y-3x+3a=0, and 3y-4x+2a=0 is (2/7)a^2dot

Prove that the area of the parallelogram contained by the lines 4y-3x-a=0,3y-4x+a=0,4y-3x-3a=0, and 3y-4x+2a=0 is (2/7)a^2dot

Prove that the area of the parallelogram contained by the lines 4y-3x-a=0,3y-4x+a=0,4y-3x-3a=0, and 3y-4x+2a=0 is (2/7)a^2dot