The horizontal and vertical displacements of a projectile are given as `x=at` & `y=bt-ct^(2)`.Then velocity of projection is

The horizontal and vertical displacements of a projectile at time t are x=36t and y=48t-4.9t^(2) respectively where x ,y are in meters and t in seconds.Initial velocity of the projectile in m/s is

The horizontal and vertical displacements of a projectile at time t are x = 36t and y = 48t -4.9t^2 respectively. lmtial velocity of the projectile in ms^-1 is

The horizontal and vertical distances covered by a projectile at tiem t are given by x=at and y= bt^(2)+ct , wehre a,b and c are constants. What is the magnitude of the velocity of the projectile 1 second after it is fired?

The horizontal and vertical displacements x and y of a projectile at a given time t are given by x= 6 "t" and y= 8t -5t^2 meter.The range of the projectile in metre is:

The horizontal and vertical displacements x and y of a projectile at a given time t are given by x= 6 "t" and y= 8t -5t^2 meter.The range of the projectile in metre is:

The horizontal and vertical displacements x and y of a projectile at a given time t are given by x = 6t metre and y = 8t-5t^2 metre. The range of the projectile in metre is

A body is projected horizontally from a point above the ground. The motion of the body is described by the equations x = 2 t and y= 5 t^2 where x and y are the horizontal and vertical displacements (in m) respectively at time t. What is the magnitude of the velocity of the body 0.2 second after it is projected?

A body is projected horizontally from a point above the ground. The motion of the body is described by the equations x = 2 t and y= 5 t^2 where x and y are the horizontal and vertical displacements (in m) respectively at time t. What is the magnitude of the velocity of the body 0.2 second after it is projected?