If (37)/(13)=2-:1/(x+1/(y+1/z)) , where ...

If `(37)/(13)=2-:1/(x+1/(y+1/z))` , where `x ,\ y ,\ z` are natural numbers, then `x ,\ y ,\ z` are (a) 1, 2, 5 (b) 1, 5, 2 (c) 5, 2, 11 (d) 11, 2, 5

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