`|(x+4, 2x, 2x),(2x, x +4, 2x),(2x, 2x ,x+4)| = (5x + 4)(4 - x)^(2)`.

By using properties of determinats. Prove that- |(x+4,2x,2x),(2x,x+4,2x),(2x,2x,x+4)| = (5x + 4) (x - 4)^2

By using properties of determinants , show that : (i) {:[( x+4, 2x, 2x),( 2x,x+4, 2x),( 2x,2x, x+4) ]:}=( 5x +4) (4-x)^(2) ( ii) {:[( y+k , y , y ),( y,y+ k , y ),( y,y , y+k ) ]:} =k^(2) ( 3y +k )

Solve : |(x+4, 2x,2x),(2x , x+4, 2x),(2x, 2x, x+4)| = 0

|{:(x+4,2x,2x),(2x,x+4,2x),(2x,2x,x+4):}|=(5x+4)(x-4)^2

det [[x + 4,2x, 2x2x, x + 4,2x2x, 2x, x + 4]]

|[x+4,2x,2x] , [2x,x+4,2x] , [2x,2x,x+4]|=(5x+4)(x-4)^2

If |(x-4,2x,2x),(2x,x-4,2x),(2x,2x,x-4)|=(A+Bx)(x-A)^2 then the ordered pair (A,B) is equal to