A force `F=(2hati+3hatj-2hatk)N` is acting on a body at point (2m, `4m,-2m)`. Find torque of this force about origin.

A force F=(2hati+3hatj+4hatk)N is acting at point P(2m,-3m,6m) find torque of this force about a point O whose position vector is (2hati-5hatj+3hatk) m.

A force F=(2hati+3hatj+4hatk)N is acting at point P(2m,-3m,6m) find torque of this force about a point O whose position vector is (2hati-5hatj+3hatk) m.

A force vecF = (hati+hatj-hatk)N acts at a point P(3 m, 6 m, 9 m). The torque exerted by this force about a point Q(2 m, 7 m, 8 m) is

A force vecF = (hati+hatj-hatk)N acts at a point P(3 m, 6 m, 9 m). The torque exerted by this force about a point Q(2 m, 7 m, 8 m) is

A force F=(2hati+3hatj-hatk)N is acting on a body at a position r=(6hati-3hatj-2hatk) . Calculate the torque about the origin

A force (hati-2hatj+3hatk) acts on a particle lying at origin. What is the torque acting on the particle about origin?

What is the torque of force vec F = (2hati -2hatj - 4hatk) N acting at a point vec r = (3hati + 2hatj) m about the origin?

A force vecF=4hati-5hatj+3hatk N is acting on a point vecr_1=2hati+4hatj+3hatk m. The torque acting about a point vecr_2=4hati-3hatk m is

A force vecF=4hati-5hatj+3hatk N is acting on a point vecr_1=2hati+4hatj+3hatk m. The torque acting about a point vecr_2=4hati-3hatk m is

A force F= 2hati+3hatj-hatk acts at a point (2,-3,1). Then magnitude of torque about point (0,0,2) will be