x sin3x

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Differentiate w.r.t x f (x) sin 3x sin^(3)x

(cos 2x sin x + cos 6x sin 3x)/(sin 2x sin x + sin 6x sin 3x) =cot 5x

x sin 3 x

If f(x) = |(sin x + sin 2x + sin 3x, sin 2x , sin 3x),(3 + 4 sin x, 3, 4 sin x),(1 + sin x, sin x, 1)| then the value of int_0^(-pi//2) f(x) dx equals :

cot 4x (sin 5x + sin 3x) = cot x (sin 5x - sin 3x)

cot 4x (sin 5x + sin 3x) = cot x (sin 5x - sin 3x)

cot 4x (sin 5x + sin 3x) = cot x (sin 5x - sin 3x)