When one mole of `CoCl_(3).5NH_(3)` was treated with excess of silver nitrate solution, 2 mol of `AgCl` was precipitated. The formula of the compound is:

When 0.01 mole of a cobalt complex is treated with excess silver nitrate solution, 4.305 g silver chloride is precipitated. The formula of the complex is

When 0.01 mole of a cobalt complex is treated with excess of silver nitrate solution 4.035 g of silver chloride is precipitated. The formula of the complex is :

The aqueous solution containing one mole of CoCl_(3).5NH_3 consumed 2 mol of silver nitrate solution for precipitation of free chloride ions. The formula of the compound should be

The aqueous solution containing one mole of CoCl_(3).5NH_3 consumed 2 mol of silver nitrate solution for precipitation of free chloride ions. The formula of the compound should be

A complex compound of cobalt contains five NH_(3) molecules. One nitro group and two chloride ions for one Co atom. One mole of this compound produces three mole ions in aq. solution. On reacting with excess of AgNO_(3) solution, two moles of AgCl get precipitated. The formula of the complex compound is

When two moles of [Co(NH_3)_5Cl]Cl_2 is treated with excess silver nitrate solution, the number of moles of silver chloride formed is