`sqrt(12+sqrt(12+sqrt(12+…………)))`

sqrt(3)sqrt(4)sqrt(12)=

sqrt27+sqrt12 =

sqrt(5sqrt(2)-2sqrt(12))=

sqrt(?)-12=sqrt(1296)

The next term in A.P., sqrt(3), sqrt(12), sqrt(27) is ……..

sqrt(12sqrt(5)+2sqrt(55))=

3sqrt2+4sqrt2+12sqrt32

(sqrt3+1)^2=?+sqrt12

(sqrt(10)+sqrt(11)+sqrt(12))xx(sqrt(10)+sqrt(11)-sqrt(12))xx(sqrt(10)-sqrt(11)+sqrt(12))xx(sqrt(10)-sqrt(11)-sqrt(12))