Home
Class 11
CHEMISTRY
How would you make up 425 mL of 0.150M H...

How would you make up 425 mL of 0.150M `HNO_3` from 68.0% `HNO_3`? The density of 68.0% `HNO_3` is1.41g/mL.

Text Solution

Verified by Experts

The correct Answer is:
`4.25`
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL CALCULATION

    NCERT TELUGU|Exercise Question ( Choose the best answer :)|17 Videos
  • CHEMICAL CALCULATION

    NCERT TELUGU|Exercise Question ( Fill in the blanks )|7 Videos
  • CHEMICAL CALCULATION

    NCERT TELUGU|Exercise EXAMPLE|3 Videos
  • BASIC CONCEPTS OF ORGANIC CHEMISTRY

    NCERT TELUGU|Exercise Questions|48 Videos
  • DETECTION AND ESTIMATION OF ELEMENTS

    NCERT TELUGU|Exercise Questions|24 Videos

Similar Questions

Explore conceptually related problems

The pH and pOH of 0.1 M aqueous solution of HNO_3 , are

What volume of 0.250 M HNO_3 reacts with 42.4 mL of 0.150 M Na_2CO_3 in the following reaction ? 2HNO_(3(aq)) + Na_2 CO_(3(aq)) to 2NaNO_(3(aq)) + H_2O_((aq)) + CO_(2(aq))

During the estimation of nitrogen in an organic compound by Kjeldhal's method, the ammonia evolved from 0.5g of the compound was absorbed in 50 ml of 0.5 M H_(2)SO_(4) . The residual acid required 60 ml of 0.5 M NaOH solution. The percentage of nitrogen in the compound is

During the estimation of nitrogen in an organic compound by Kjeldhal's method, the ammonia evolved from 0.5g of the compound was absorbed in 50 ml of 0.5 M H_(2)SO_(4) . The residual acid required 60 ml of 0.5 M NaOH solution. The number of grams of NH_(3) releaed in the process is

Molarity of a 50 mL H_2SO_4 solution is 10.0 M. If the density of the solution is 1.4 g/cc, calculate its molality

A sample of 0.50 g of an organic compound was treated according to Kjeldahl’s method. The ammonia evolved was absorbed in 50 ml of 0.5 M H_(2)SO_(4) . The residual acid required 60 mL of 0.5 M solution of NaOH for neutralisation. Find the percentage composition of nitrogen in the compound.

The pH of the resultant solution of 20 ml of 0.1 M H_3PO_4 and 20 ml 0.1 M Na_3PO_4 is

NCERT TELUGU-CHEMICAL CALCULATION -Problems of Practice
  1. A compound contains 32% carbon, 4% hydrogen and rest oxygen. Its vapou...

    Text Solution

    |

  2. An acid of molecular mass 104 contains 34.6% carbon, 3.85% hydrogen an...

    Text Solution

    |

  3. What is the simplest formula of the compound which has the following p...

    Text Solution

    |

  4. Calculate the oxidation number of underlined elements in the following...

    Text Solution

    |

  5. Calculate the oxidation number of underlined elements in the following...

    Text Solution

    |

  6. Calculate the oxidation number of underlined elements in the following...

    Text Solution

    |

  7. Calculate the oxidation number of underlined elements in the following...

    Text Solution

    |

  8. Calculate the oxidation number of underlined elements in the following...

    Text Solution

    |

  9. Balance the equations Mg + NO3^(-) to Mg^(2+) + N2O + H2O) ( in acidi...

    Text Solution

    |

  10. Balance the equations Cr^(3+) + Na2O2 to CrO4^(-) + Na^(+)

    Text Solution

    |

  11. Balance the equations S^(2-) + NO3^(-) to NO + S

    Text Solution

    |

  12. Balance the equations FeS + O2 to Fe2O3 + SO2 ( molecular form )

    Text Solution

    |

  13. In the reaction : Cl2 + OH^(-) rarr Cl^(-) +ClO(4)^(-) +H(2)O chlorine...

    Text Solution

    |

  14. Calculate the volume of 14.3m NH3, solution needed to prepare 1L of 0....

    Text Solution

    |

  15. How would you make up 425 mL of 0.150M HNO3 from 68.0% HNO3? The densi...

    Text Solution

    |

  16. Calculate the molarity of a solution obtained by mixing 100 mL of 0.3 ...

    Text Solution

    |

  17. Calculate the molality of a solution by dissolving 0.850g of ammonia (...

    Text Solution

    |

  18. NiSO4 reacts with Na3PO4 to give a yellow green precipitate of Ni3 (PO...

    Text Solution

    |

  19. What volume of 0.250 M HNO3 reacts with 42.4 mL of 0.150 M Na2CO3 in t...

    Text Solution

    |

  20. A flask contains 53.1 mL of 0.0150 M Ca(OH)2 solution. How many mL of ...

    Text Solution

    |