Home
Class 11
CHEMISTRY
At room temperature, Polonium (atomic we...

At room temperature, Polonium (atomic weight `209 gm mol^(-1)`) crystallises in a primitive cubic unit cell. If `a = 3.36 A^(0)`, calculate the theoritical density of Polonium.. 

Text Solution

Verified by Experts

A primitive cubic unit cell contains atoms only at the 8 corners with each corner contributing `1//8^(th)` of an atom . Hence n = `8 xx (1//8) = 1` . Volume `V = a^(3) = (3.36 Å)^(3)`
From Eq. 1 `rho = (n M m)/(N_(0) V)`
`= ((1) 209 g mol^(-1)))/((6.022 xx 10^(23) mol^(-1)) (3.36 xx 10^(-8) cm)^(3))`
`= 9.15 g cm^(-3)`
Promotional Banner

Topper's Solved these Questions

  • THE SOLID STATE - I

    NCERT TELUGU|Exercise Problems|4 Videos
  • THE SOLID STATE - I

    NCERT TELUGU|Exercise QUESTIONS (CHOOSE THE BEST ANSWER)|9 Videos
  • THE s-BLOCK ELEMENTS

    NCERT TELUGU|Exercise EXERCISES|32 Videos

Similar Questions

Explore conceptually related problems

Metallic chromium crystallises in bee lattice. The edge length of unit cell is 2.87 A^(0) . Calculate (a) atomic radius and (b) density.

Metallic chromium crystallises in bcc lattice. The edge length of unit cell is 2.87 A_0. Calculate (a) atomic radius and (b) density.

Silicon crystallises in fcc lattice, a single crystal of high purity like diamond. Gram atomic weight of silicon is 28 g mol^(-1) . Edge length of unit cell is 0.543nm. Calculate the number of silicon atoms per unit cell and density of unit cell.

Silicon crystallises in foc lattice, a single crystal of high purity like diamond. Gram atomic weight of silicon is 28 g mol^(-) . Edge length of unit cell is 0.543nm. Calculate the number of silicon atoms per unit cell and density of unit cell.

Atomic weight of silver is 107 .8. Silver crystallises in fee lattice with edge length of unit cell is 4.086 A^0 . Calculate the density of unit cell of silver and radius of silver atom.

A metal crystallises in fcc lattice with edge length of unit cell 3.5 A^(0) and also in bcc lattice with edge length of unit cell 3A^(0) . Calculate the ratio of the densities of fcc and bcc lattices.

The edge length of unit cell of metal having molecular weight 75g//mol is 5Å which crystallises in simple cubic lattice. If the density is 2g/cc then the radius of metal atom in pm is x xx 10^(2) then 'x' is (N_(A) = 6 xx 10^(23))

X-ray diffraction studies show that copper crystallises in an fcc unit cell with cell edge of 3.608 xx 10^(-8) cm . In a separate experiment , copper is determined to have a density of 8.92 g/ cm^(3) , calculate the atomic mass of copper .