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cos ^(2) 2x -cos ^(2) 6x = sin 4x sin 8x...

`cos ^(2) 2x -cos ^(2) 6x = sin 4x sin 8x`

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Knowledge Check

  • If 3 cos x ne 2 sin x , then the general solution of sin^(2) x - cos 2x = 2 - sin 2x is x =

    A
    `n pi + (-1)^(n) (pi)/(2), n in Z`
    B
    `(n pi)/(2), n in Z`
    C
    `(4n pm 1)(pi)/(2), n in Z`
    D
    `(2n - 1) pi, n in Z`

  • The number of solutions of sin^(2) x cos^(2) x = 1 + cos^(2) x sin^(4) x in the inverval [0, 2 pi] is

    A
    no solution
    B
    1
    C
    2
    D
    3

  • Number of solutions of equation 2 sin (x)/(2) cos ^(2) x - 2 sin "" (x)/(2) sin ^(2) x = cos^(2) x - sin ^(2) x " for " x in [0, 4 pi]

    A
    6
    B
    8
    C
    10
    D
    12

    • Similar Questions

    Explore conceptually related problems

    The number of distinct solutions of (5)/(4) cos ^(2) 2 x + cos ^(4) x + sin^(4) x + cos ^(6) x + sin ^(6) x = 2 is [0, 20 pi]

    Show that int_(0)^(pi//4)(dx)/(cos^(4)x - cos^(2)x sin^(2) x + sin^(4)x) = (pi)/(2)

    Show that int_(0)^(pi/4)(dx)/(cos^(4)x - cos^(2)x sin^(2) x + sin^(4) x) = pi/2

    Show that the range of the function f(x ) = (sin^(2) x + cos^(4) x)/( cos^(2) x+ sin^(4) x ) is a singleton set.

    int_(-pi//2)^(pi//2) sin^(2) x cos^(2) x(sin x + cos x) dx=

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