A bus is moving with the initial velocity of 'u' m/s. After applying the breaks, its retardation is 0.5 m/`s^(2)` and it stoped after 12s. Find the initial velocity (u) and distance travel by the bus after applying the breaks.

Explanation

a = 0.5 `m//s^(2)`
v = 0 m/s
t = 12 s
u = ?
v = u + at
0 = u + `(-0.5 xx 12 )`
0 = u - 6
u = 6 m/s
Initial velocity of the bus 6 m/s .
s = ut + `(1)/(2) at^(2)`
= `( 12 xx 6 ) + (1)/(2) ( - 0.5 xx 12^(2) )`
= 72 -` (1)/(2) (72)`
= 36 m
Bus has stoped 36 m distance after applying the break