A Container having 1 mole of a gas at a temperature `27^(@)` has a movable piston which maintains at constant pressure in container of 1 atm . The gas is compressed until temperature becomes `127^(@)`. The work done is ( C for gas is 7.03 cal / mol – K )

A cylinder contains 3 moles of oxygen at a temperature of 27^(@)C . The cylinder is provided with a frictionless piston which maintains a constant pressure of 1 atm on the gas. The gas is heated until its temperature rises to 127^(@)C . a. How much work is done by the gas in the process ? b. What is the change in the internal energy of the gas ? c. How much heat was supplied to the gas ? For oxygen C_(P) = 7.03 cal mol^(-1) .^(@)C^(-1) .

A cylinder contains 3 moles of oxygen at a temperature of 27^(@)C . The cylinder is provided with a frictionless piston which maintains a constant pressure of 1 atm on the gas. The gas is heated until its temperature rises to 127^(@)C . a. How much work is done by the gas in the process ? b. What is the change in the internal energy of the gas ? c. How much heat was supplied to the gas ? For oxygen C_(P) = 7.03 cal mol^(-1) .^(@)C^(-1) .

Temperature of 1mol of a gas is increased by 1^(@) at constant pressure. The work done is

Temperature of 1mol of a gas is increased by 1^(@) at constant pressure. The work done is

Temperature of 1mol of a gas is increased by 1^(@) at constant pressure. The work done is

Work done by 0.1 mole of a gas at 27^(@)C to double its volume at constant pressure is (R=2" cal mol"^(-1).^(@)K^(-1))

One mole of and ideal monoatomic gas is compressed isothermally in a rigid vessel to double its pressure at room temperature, 27^(@)C . The work done on the gas will be :