`1+ tan A tan .(A)/(2)= tan A cot (A)/(2) -1 =sec A`

(sec 8 A-1)/( sec 4A-1)= ..................... A) (tan 2A)/( tan 8A) B) (tan 8A)/(tan 2A) C) (cot 8A)/(cot 2A) D) (tan 6A)/(tan 2A)

Prove that : (sec A - cosec A ) (1 + tan A + cot A)= tan A sec A-cot A cosec A .

(tan A) / (1-cot A) + (cot A) / (1-tan A) = 1 + tan A + cot A = 1 + sec A cos ecA

Prove that : (tan A)/ (1 - cot A) + (cot A)/ (1 - tan A) = sec A cosec A + 1

Prove the following identities: (1+tan A tan B)^(2)+(tan A-tan B)^(2)=sec^(2)A sec^(2)B(tan A+csc B)^(2)-(cot B-sec A)^(2)=2tan A cot B(csc A+sec B)

(1+ (tan A) / (2)) / (1- (tan A) / (2)) = sec A + tan A

Prove that (tan A-tan B)^(2)+(1+tan A tan B)^(2)=sec^(2)A sec^(2)B

1+tan A tan2A=sec2A

Prove the following identities : (sec A - tan A)/ (sec A + tan A) = 1 - 2 sec A tan A + 2 tan^(2) A