A particle is executing simple harmonic motion between exterme positions given by `(-1,-2,-3)cm` and `(1,2,1)cm`. Its amplitude of oscillation is

The displacement of a particle executing simple harmonic motion is given by y=A_(0)+A sin omegat+B cos omegat . Then the amplitude of its oscillation is given by

The displacement of a particle executing simple harmonic motion is given by y=A_(0)+A sin omegat+B cos omegat . Then the amplitude of its oscillation is given by

The displacement of a particle executing simple harmonic motion is given by y=A_(0)+Asinomegat+Bcosomegat Then the amplitude of its oscillation is given by :

The position and velocity of a particle executing simple harmonic motion at t = 0 are given by 3 cm and 8 cm s^(-1) respectively . If the angular frequency of the particle is 2 "rad s" ^(-1) , then the amplitude of oscillation (in cm) is

The position and velocity of a particle executing simple harmonic motion at t = 0 are given by 3 cm and 8 cm s^(-1) respectively . If the angular frequency of the particle is 2 "rad s" ^(-1) , then the amplitude of oscillation (in cm) is

A particle is executing simple harmonic motion with a time period of 2s and amplitude 10 cm. Calculate its velocity and acceleration 2 seconds after starting from mean position.

A particle is executing simple harmonic motion. The velocity of the particle is 10 m s^(-1) . What at a distance of 5 cm from mean position and 8 cm s^(-1) when at a distance of 12 cm from mean position. What will be the amplitude of motion ?

A particle is executing simple harmonic motion with time period of 4 s and amplitude 10 cm. Calculate displacement, velocity after (1)/(2) second starting from mean position.

A particle is executing simple harmonic motion with an amplitude of 10 cm and time period of 4s. Calculate its displacement, velocity and acceleration after 1/2 seconds, starting from the mean position.