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sum(n=1)^ootan(theta/(2^n))/(2^(n-1)cos(...

`sum_(n=1)^ootan(theta/(2^n))/(2^(n-1)cos(theta/(2^(n-1))))`

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Statement I Pi_(r=1)^(n) (1+sec 2^(r)theta)=tan 2^(n)theta cot theta Statement II Pi_(r=1)^(n) cos (2^(r-1)theta)=(sin(2^(n)theta))/(2^(n)sin theta)

Statement I Pi_(r=1)^(n) (1+sec 2^(r)theta)=tan 2^(n)theta cot theta Statement II Pi_(r=1)^(n) cos (2^(r-1)theta)=(sin(2^(n)theta))/(2^(n)sin theta)

The sum sum _(n=1)^ootan^(-1)(1/(2^n+2^(1-n))) equals