If `y=mx+1` and `y^(2)=4x+1` then `m=`

The line y=mx+1 touches y^(2)=4x , if m = …………

Length of the chord intercepted by the parabola y^(2)=4ax on the line y=mx+c is :((4)/(m^(2)))sqrt(a(1+m^(2))(a+mc))

If the straight line y=mx+1 be the tangent of the parabola y^(2)=4x at the point (1,2) then the value of m will be-

If the line y = mx + 1 is tangent to the parabola y^(2) = 4x then find the value of m.

If the line y=mx+1 is tangent to the parabola y^(2)=4x, then find the value of m .

If the are between y =mx^(2) and x= my^(2) (m gt 0 ) is (1)/(4) sq . Unit then the value of m is:

If the lines y = 3x +1 and 2y = x + 3 are equally inclined to the line y= mx + 4, find the value of m.