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In Fig. four particles form a square. Th...

In Fig. four particles form a square. The charges are `q_(1) = q_(4) = Q` and `q_(2) = q_(3) = q`. (a) What is Q/q is the net electrostatic force on particles 2 and 3 is zero ? (b) Is there any value of q makes the net electrostatic force on each of the four particles zero ? Explain.

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(a) -0.354, (b) No
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Knowledge Check

  • A charge particle q_(1) , is at position (2, -1, 3). The electrostatic force on another charged particle q_(2) at (0, 0, 0) is :

    A
    `(q_(1)q_(2))/(56 pi in_(0)) (2hat(i)-hat(j)+3hat(k))`
    B
    `(q_(1)q_(2))/(56 sqrt(14) pi in_(0)) (2hat(i)-hat(j)+3hat(k))`
    C
    `(q_(1)q_(2))/(56 pi in_(0)) (hat(j)-2hat(i)-3hat(k))`
    D
    `(q_(1)q_(2))/(56 sqrt(14) pi in_(0)) (hat(j)-2hat(i)-3hat(k))`

  • Three charges Q, +q and +q are placed at the vertices of a right-angled isosceles triangle as shown. The net electrostatic energy of the configuration is zero if Q is equal to

    A
    (a) `(-q)/(1+sqrt2)`
    B
    (b) `(-2q)/(2+sqrt2)`
    C
    (c) `-2q`
    D
    (d)`+q`
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