A charged particle creates an electric field of magnitude 300 N/C at a point 0.800 m away. What is the difference in the field magnitude between that point and one at 0.400 m ?

Explanation

To solve the problem step by step, we will follow these steps:

### Step 1: Understand the relationship between electric field and charge
The electric field \( E \) created by a point charge \( Q \) at a distance \( R \) is given by the formula:
\[ E = \frac{1}{4 \pi \epsilon_0} \frac{Q}{R^2} \]
Where:
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