An electric dipole consisting of charges of magnitude `1.50 nC` separated by 6.20 `mu m` is in an electric field of strength 300 N/C. what are (a) the magnitude of the electric dipole moment and (b) the difference between the potential energies for dipole orientations parallel and perpendicular to `vec(E)` ?

Explanation

To solve the problem, we will break it down into two parts: (a) calculating the electric dipole moment and (b) finding the difference in potential energies for the dipole orientations parallel and perpendicular to the electric field.

### (a) Magnitude of the Electric Dipole Moment

1. **Identify the given values**:
- Charge (Q) = 1.50 nC = \(1.50 \times 10^{-9}\) C
- Separation distance (d) = 6.20 µm = \(6.20 \times 10^{-6}\) m

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