At some instant the velocity components of an electron moving between two charged parallel plates are `v_x=1.5xx10^5m//s` and `v_y=3.0xx10^6 m//s`.Suppose that the electric field between the plates is given by `E = (120 N//C) hatj`
. (a) What is the acceleration of the electron?
(b) What will be the velocity of the electron after its x-coordinate has changed by 2.0 cm?

Explanation

(a) `-(2.1 xx 10^(13) m//s^(2))hat(j)`, (b) `(2.5 xx 10^(13) m//s^(2)) hat(i) - (1.7 xx 10^(6) m//s) hat(j)`