A charged particles produces an electric field with a magnitude of 2.0 N/C at a point that is 50 cm away from the particle. What is the magnitude of the field at an additional distance of 2.5 cm ?

Explanation

To solve the problem, we need to determine the electric field at a distance of 52.5 cm from the charged particle, given that the electric field at 50 cm is 2.0 N/C.

### Step-by-Step Solution:

1. **Understand the relationship of electric field and distance**: The electric field \(E\) due to a point charge is given by the formula:
\[ E = \frac{k \cdot |q|}{r^2} \]
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