A liquid of density 900 kg/m flows through a horizontal pipe that has a cross-sectional area of `1.90 xx 10^(-2) m^(2)` in region A and a cross-sectional area of `9.50 xx 10^(-2) m^(2)` in region B. The pressure difference between the two regions is `720 xx 10^(3)` Pa. What are (a) the volume flow rate and (b) the mass flow rate?

Explanation

To solve the problem, we will follow these steps:

### Step 1: Understand the Given Data
- Density of the liquid, \( \rho = 900 \, \text{kg/m}^3 \)
- Cross-sectional area at region A, \( A_A = 1.90 \times 10^{-2} \, \text{m}^2 \)
- Cross-sectional area at region B, \( A_B = 9.50 \times 10^{-2} \, \text{m}^2 \)
- Pressure difference between the two regions, \( \Delta P = P_B - P_A = 720 \times 10^{3} \, \text{Pa} \)

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