A partially evacuated airtight container has a tight-fitting lid of surface area 50 `cm^(2)` and negligible mass. If the force required to remove the lid is 480 N and the atmospheric pressure is `1.0`x `10^(5)` Pa, what is the internal air pressure?

Explanation

To solve the problem, we need to find the internal air pressure in a partially evacuated airtight container. We know the force required to remove the lid, the atmospheric pressure, and the surface area of the lid.

### Step-by-Step Solution:

1. **Identify Given Values:**
- Force required to remove the lid (F) = 480 N
- Atmospheric pressure (Pₐ) = 1.0 x 10⁵ Pa
- Area of the lid (A) = 50 cm² = 50 x 10⁻⁴ m² (convert to m²)
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