Water is pumped steadily out of a flooded basement at 4.5 m/s through a hose of radius 1.0 cm, passing through a window 3.5 m above the waterline. What is the pump's power?

Explanation

To find the power of the pump that is moving water out of a flooded basement, we can follow these steps:

### Step 1: Identify the given values
- Velocity of water, \( V = 4.5 \, \text{m/s} \)
- Radius of the hose, \( r = 1.0 \, \text{cm} = 0.01 \, \text{m} \)
- Height of the window above the waterline, \( h = 3.5 \, \text{m} \)
- Density of water, \( \rho = 1000 \, \text{kg/m}^3 \) (standard value)

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