Three liquids that will not mix are poured into a cylindrical container. The volumes and densities of the liquids are 1.50 L, 2.6 g/`cm^(3)`: 0.75 L, 1.0 g/`cm^(3)` , and 0.60 L, 0.80 g/`cm^(3)`. What is the force on the bottom of the container due to these liquids? One liter = 1 L = 1000 `cm^(3)` (Ignore the contribution due to the atmosphere.)

Explanation

To solve the problem, we need to calculate the total force exerted on the bottom of the cylindrical container due to the three liquids. The force is equal to the weight of the liquids, which can be calculated using the formula:

\[ F = m \cdot g \]

Where:
- \( F \) is the total force,
- \( m \) is the total mass of the liquids,
- \( g \) is the acceleration due to gravity (approximately \( 9.8 \, \text{m/s}^2 \)).
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