A wood block (mass 3.67 kg, density 600 kg/m) is fitted with lead (density `1.14 xx 10^(4) kg//m^(3)`) so that it floats in water with 0.700 of its volume submerged. Find the lead mass if the lead is fitted to the block's (a) top and (b) bottom

Explanation

To solve the problem, we need to analyze the situation in two parts: when the lead is fitted to the top of the wood block and when it is fitted to the bottom. We will use the principle of buoyancy, which states that the weight of the fluid displaced is equal to the weight of the object.

### Given Data:
- Mass of wood block, \( m_1 = 3.67 \, \text{kg} \)
- Density of wood block, \( \rho_1 = 600 \, \text{kg/m}^3 \)
- Density of lead, \( \rho_2 = 1.14 \times 10^4 \, \text{kg/m}^3 \)
- Submerged volume fraction, \( V_s = 0.7 \)

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