A block of wood floats in fresh water with two-thirds of its volume V submerged and in oil with 0.92V submerged. Find the density of (a) the wood and (b) the oil.

Explanation

To solve the problem, we will follow these steps:

### Step 1: Determine the density of the wood.
When the block of wood floats in fresh water, two-thirds of its volume \( V \) is submerged. According to Archimedes' principle, the buoyant force acting on the block is equal to the weight of the water displaced by the submerged volume of the block.

Let:
- \( \rho_w \) = density of water = 1000 kg/m³
- \( \rho_{wood} \) = density of wood
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