A circle is circumscribed around a square as shown in the figure. The area of one of the four shaded portions is equal to `4/7` . The radius of the circle is (FIGURE) `sqrt(2)` (b) `1/(sqrt(2))` (c) 2 (d) 3

In the adjoining figure,if the radius of each of the four outer circles is r, what is the radius of the inner circle? (FIGURE) (a) (2)/(sqrt(2)+1)r(b)(1)/(sqrt(2))r(c)(sqrt(2)-1)r(d)sqrt(2)backslash r

The area of a square is equal to the area of a circle. The ratio between the side of the square and the radius of the circle is (a) sqrt(pi):1 (b) 1:sqrt(pi) (c) 1:pi (d) pi:1

In the figure, O is the centre of the circle. anglePOQ=90^@ . The area of the shaded region is 126cm^2 . Find the radius of the circle.

The area of a square is equal to the area of a circle.The ratio between the side of the square and the radius of the circle is (a) sqrt(pi):1 (b) 1:sqrt(pi)(c)1:pi(d)pi:1

A B C D is a square of unit area. A circle is tangent to two sides of A B C D and passes through exactly one of its vertices. The radius of the circle is (a) 2-sqrt(2) (b) sqrt(2)-1 (c) sqrt(2)-1/2 (d) 1/(sqrt(2))

A B C D is a square of unit area. A circle is tangent to two sides of A B C D and passes through exactly one of its vertices. The radius of the circle is (a) 2-sqrt(2) (b) sqrt(2)-1 (c) sqrt(2)-1/2 (d) 1/(sqrt(2))

The line 2x-y+1=0 is tangent to the circle at the point (2, 5) and the center of the circle lies on x-2y=4. The radius of the circle is (a) 3sqrt(5) (b) 5sqrt(3) (c) 2sqrt(5) (d) 5sqrt(2)

A B C D is a square of unit area. A circle is tangent to two sides of A B C D and passes through exactly one of its vertices. The radius of the circle is a) 2-sqrt(2) b) sqrt(2)-1 c) 1//2 d) 1/(sqrt(2))

In the following figure, if PQ = R (P is the centre of the bigger circle) and the shaded area is equal to A, then the radius of the inner circle is equal to -