A boy throws a ball upward with velocity `v_(0)=20m//s`. The wind imparts a horizontal acceleration of `4m//s^(2)` to the left. The angle `theta` at which the ball must be thrown so that the ball returns to the boy's hand is : `(g=10ms^(-2))`

A boy throws a ball up ward with a speed of 12m/s The wind imparts a horizontal acceleration of 0.4 m//s^(2) . At what angle theta to the vertical, the ball must be thrown so that it returns to the point of release.

A boy throws a ball at an angle theta with the vertical. If the vertical component of the initial velocity is 20ms^(-1) and the wind imparts a horizontal acceleration of 8ms^(-2) to the left, the angle at which the ball must be thrown so that the ball returns to the boy's hand is theta . What is the value of 10(tan theta)

A boy throws a ball at an angle theta with the vertical. If the vertical component of the initial velocity is 20ms^(-1) and the wind imparts a horizontal acceleration of 8ms^(-2) to the left, the angle at which the ball must be thrown so that the ball returns to the boy's hand is theta . What is the value of 10(tan theta)

A boy throws a ball with a velocity of 15 m/s at an angle of 15° with the horizontal. The distance at which the ball strikes the ground is

A boy throws a ball with a velocity of 15 m/s at an angle of 15° with the horizontal. The distance at which the ball strikes the ground is

A boy throws a ball of mass 200g with a velocity 20ms^-1 at an angle of 40° with the horizontal. What is the kinetic energy of the ball at the highest point of the trajectory?