`(dy/dx)^2+1/[dy/dx]=2`

Solve x{(dy/dx)^2+dy/dx}=y

Solve 1+(dy/dx)^2=xdy/dx

x^2(dy/dx)^2-2xy dy/dx+2y^2-x^2=0

Find the order and degree of the following differential equations. i) (dy)/(dx)+y=1/((dy)/(dx)) , ii) e^(e^(3)y)/(dx^(3))-x(d^(2)y)/(dx^(2))+y=0 , iii) sin^(-1)(dy)/(dx)=x+y , iv) log_(e)(dy)/(dx)=ax+by v) y(d^(2)y)/(dx^(2))+x((dy)/(dx))^(2)-4y(dy)/(dx)=0

What is the order of the differential equation ? (dy)/(dx)+y=1/((dy)/(dx))

Obtain all the solutions of (y+1)(dy/dx)+2=x(dy/dx)^2

find the order and degree of D.E : (1) ((d^(2)y)/(dx^(2) ))^2 + ((dy)/(dx))^(3) = e^(x) (2) sqrt(1 + 1/((dy)/(dx))^(2))= ((d^(2)y)/(dx^(2)))^(3/2) (3) e^((dy)/(dx))+ (dy)/(dx) =x