If `x,y,z` are real numbers such that `xy=6,x-z=2` and `x+y+z=9,` compute `(x)/(y)-(z)/(x)-(z^(2))/(xy)`

(x)/(y)*(y)/(xz)*(z^(2))/(xy)

If x,y and z are three numbers such that x+y=13,y+z=15 and z+x=16,then the value of (xy+xz)/(xyz) is:

When x,y,z are real solve the equation x+y=2 and xy-z^(2)=1

Let x, y, z be non-zero real numbers such that x/y + y/z + z/x = 7 and y/x + z/y + x/z = 9 , then (x^3)/y^3 + y^3/z^3 + z^3/x^3 - 3 is equal to

If x.y,z are positive real numbers such that x^(2)+y^(2)+z^(2)=27, then x^(3)+y^(3)+z^(3) has

If x,y,z are three real numbers of the same sign then the value of (x)/(y)+(y)/(z)+(z)/(x) lies

Simplify- (x-y)/(xy)+(y-z)/(yz)+(z-x)/(zx)