`3a^2+4a(3a-4b)-20ab`

Using formula let's show that. (3a-4b)^2 + 24ab = 9a^2 +16b^2

Subtract the second polynomial from the first: 2ab^2+3a^2b-4ab,3ab-8ab^2+2a^2b

Subtract the second polynomial from the first: 2ab^2 +3a^2 b -4ab , 3ab-8ab^2 +2a^2 b .

Evaluate (4a+3b)^2-(4a-3b)^2+48ab

The factors of 8a^(3)+b^(3)-6ab+1 are (a) (2a+b-1)(4a^(2)+b^(2)+1-3ab-2a) (b) (2a-b+1)(4a^(2)+b^(2)-4ab+1-2a+b)(2a+b+1)(4a^(2)+b^(2)+1-2ab-b-2a) (d) (2a-1+b)(4a^(2)+1-4a-b-2ab)

If a+b=1 , then a^(4)+b^(4)-a^(3)-b^(3)-2a^(2)b^(2)+ab is equal to :

Find the product of the following. (a^2+4b^2+2ab-3a+6b+9)(a-2b+3)

Simplify the following . 3a^(2)-4a^(2)b+7a^(2)-b^(2)-ab