A body of mass `2 kg` is thrown up vertically with kinetic energy of `490 J`. If `g = 9.8m//s^(2)`, the height at which the kinetic energy of the body becomes half of the original value, is

A body of mass 5 kg is thrown vertically up with a kinetic energy of 490 J. What will be height at which the kinetic energy of the body becomes half of the original value ? (Acceleration due to gravity =9.8ms^(-2) )

A body of mass 5 kg is thrown vertically up with a kinetic energy of 490 J. What will be height at which the kinetic energy of the body becomes half of the original value ? (Acceleration due to gravity =9.8ms^(-2) )

A body of mass 5 kg is thrown vertically up with a kinetic energy of 490 J.The height at which the kinetic energy of the body becomes half of the origibnal value is

A body of mass 5kg is thrown up vertically with a kinetic energy of 1000J . If acceleration due to gravity is 10ms^(-2) , find the height at which the kinetic energy becomes half of the original value.