A constant torque of `31.4 N-m` id exterted on a pivoted wheel. If the angular acceleration of the wheel is `4 pi rad//s^2`, then the moment of inertia will be.

A constant torque of 3.14 N.m is exerted on a pivoted wheel. If the angular acceleration of the wheel is 4pi"rad".s^(-2) , then the moment of inertia of the wheel is

A constant torque of 31.4 Nm is applied to a pivoted wheel. If the angular acceleration of the wheel is 2pi" rad/s"^(2) , then its moment of inertia is

A constant net torque equal to 20 N-m is exerted on a pivoted wheel for 8 sec, during which time the angular velocity of the wheel increases from zero to 100 re // min. The external torque is then removed and the wheel is brought to rest by friction in its bearings in 70 sec. Compute (a) the moment of inertia of the wheel about the rotation axis, (b) the friction torque(c)thetotal no. of revolutions made by the wheel in the70 sec time interval

The torque acting is 2000 Nm with an angular acceleration of 2rad//s^(2) . The moment of inertia of body is

A torque of 100 Nm acting on a wheel at rest, rotatesit through 200 radiansin10 s.The angular acceleration of the wheel, in rad/s^2 is

A cord is wound around the circumference of a wheel of diameter 0.3 m. The axis of the wheel is horizontal. A mass of 0.5 kg is attached at the end of the cord and it is allowed to fall from rest. If the weight falls 1.5 m in 4s, what is the angular acceleration of the wheel ? Also find out the moment of inertia of the wheel.