A particle is projected from ground at an angle `45^(@)` with initial velocity `20sqrt2 ms^(-1)`.The magnitude of average velocity in a timer interval from `t=0` to `t=3 s` in `ms^(-1)` is

A particle is projected from ground at angle 45^@ with initial velocity 20(sqrt2) m//s . Find (a)change in velocity, (b)magnitude of average velocity in a time interval from t=0 to t=3s .

A particle is projected from ground at angle 45^@ with initial velocity 20(sqrt2) m//s . Find (a) change in velocity, (b) magnitude of average velocity in a time interval from t=0 to t=3s .

A particle is projected from ground with speed 80 m/s at an angle 30^(@) with horizontal from ground. The magnitude of average velocity of particle in time interval t = 2 s to t = 6 s is [Take g = 10 m//s^(2)]

A particle is projected from ground with speed 80 m/s at an angle 30^(@) with horizontal from ground. The magnitude of average velocity of particle in time interval t = 2 s to t = 6 s is [Take g = 10 m//s^(2)]

A particle is projected from the ground with an initial velocity of 20m//s at an angle of 30^(@) with horizontal. The magnitude of change in velocity in a time interval from t=0 to t=0.5s ( g=10m//s^(2) )

A particle is projected at an angle theta =30^@ with the horizontal, with a velocity of 10ms^(-1) . Then

A particle is projected at an angle theta =30^@ with the horizontal, with a velocity of 10ms^(-1) . Then

A particle is projected from ground with velocity 40sqrt2m at 45^(@) .At time t=2s

A particle is projected from horizontal making an angle of 53^(@) with initial velocity 100 ms^(-1) . The time taken by the particle to make angle 45^(@) from horizontal is

A particle is projected from horizontal making an angle of 53^(@) with initial velocity 100 ms^(-1) . The time taken by the particle to make angle 45^(@) from horizontal is